InterviewSolution
Saved Bookmarks
| 1. |
A magentic field directed into the page changes with time according to `B = (0.0300t^(2) + 1.4.40)T`, where `t` is in seconds. The field has a circular cross section of radius `R = 2.50 cm`. What are the magitude and direction of the electric field at point `P_(1)` when `t = 3.00 s` and `r_(1) = 0.0200 m`? |
|
Answer» `(dB)/(dt) = 0.060 t` `E_(atP_(1)) = (r )/(2) (dB)/(dt) = (0.020)/(2) xx 0.060 = 6 xx 10^(-4) V//m` Here magentic field is increasing with time hence electric field will be in anticlockwise direction. |
|