InterviewSolution
Saved Bookmarks
| 1. |
In an `LC` circuit as shows in Fig. the switch is closed at `t = 0`.`Q_(max) = 100 mu C`, `L = 40 mH`, `C = 100 mu F`. a. Determine the equation for instantaneous change on the capacitor. b. Determine the equation for instantaneous current in the circuit. |
|
Answer» a. `q = Q_(max) cos omega t`, Here `Q_(max) = 100 mu C`, `omega = (1)/(sqrt(LC)) =(1)/(sqrt((40 xx 10^(-3))(100 xx 10^(-6)))) = 500 rads^(-1)` `q = 100 cos (500t) mu C` b. `i = (-dq)/(dt) = (100) (500) sin (500t) mu A` or `i = 50000 sin (500t) mu A` |
|