1.

In an n-p-n transistor circuit , the collector current is 10 mA . If 90% of the electrons emitted reach the collector , the emitter current I_e and base current I_b are given be :

Answer»

`I_e = 9MA , I_b=-1MA`
`I_e = -1mA , I_b=9mA`
`I_e = 1mA , I_b=11mA`
`I_e = 11mA , I_b=1mA`

SOLUTION :`i_c=10 mA= 0.9 I_e`
`i_e=10/(0.9)=11 mA`
Now , `i_e=i_c+i_b`
`:. i_b=I_e-i_c=11-10=1mA`


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