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In an Ostwald viscometer, water takes 25 s to flow between the lower and upper marks, while the liquid X takes 38 s. Given d(H_(2)O) = 0.9983 kg//dm^(3), d(X) = 0.7894 kg//dm^(3), eta(H_(2)O) = 1.005centipoise. Calculate eta of liquid X |
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Answer» Solution :`eta_(1)/eta_(2) = (t_(1).d_(1))/(t_(2).d_(2))` Suppose 1 and 2 stand for X and water RESPECTIVELY. `eta_(1)/(1.005) = (38 XX 0.7894)/(25 xx 0.9983)` `eta_(1) = 1.208` centipose. |
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