In an P.N.P transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector.

In an P.N.P transistor circuit, the collector current is 10 mA. If 90%

1.	In an P.N.P transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector.
Answer» Solution :Here, `I_E=10mA` As 90% of the holes REACH the COLLECTOR, so the collector, so the collector currents. `I_C=90%of I_E` `I_C=(90)/(100)I_E` `I_E=(100)/(90)I_C=(100)/(90)xx10` `I_E~=11mA` BASE current, `I_B=I_E-I_C=11-10` `I_B=1 mA`

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In an P.N.P transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector.

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