In an RC series circuit(in fig), the rms voltage of source is 200V and its frequency is 50 Hz, if `R=100 Omega and C=(100)/(po) (mu)F`, find (a) inpedance of the circuit. (b) power factor angle, (c ) power factor, (d) current, (e) maximum current (f) voltage across R, (g) voltage across C, (h) maximum voltage across R, (i) maximum voltage across C, (j) ltPgt, (k) ` gtP_(C )lt`. `(m) i(t)`, `V_(R )(t),and V_(C)(t)`.

In an RC series circuit(in fig), the rms voltage of source is 200V and

1.	In an RC series circuit(in fig), the rms voltage of source is 200V and its frequency is 50 Hz, if `R=100 Omega and C=(100)/(po) (mu)F`, find (a) inpedance of the circuit. (b) power factor angle, (c ) power factor, (d) current, (e) maximum current (f) voltage across R, (g) voltage across C, (h) maximum voltage across R, (i) maximum voltage across C, (j) ltPgt, (k) ` gtP_(C )lt`. `(m) i(t)`, `V_(R )(t),and V_(C)(t)`.
Answer» `X_(C)=(10^(6))/((100)/(pi)(2pi50))=100Omega` (i) `Z=sqrt(R^(2)+X_(c^(2))=sqrt(100^(2)+(100)^(2)=100sqrt2Omega` (ii) `tan phi =(X_(c))/(R )=1 therefore phi-=45^(@)` (iii) `"Power factor"=cos phi=(1)/(sqrt2)` `(iv)"Current" I_("rms")=(V_(rms"))/(Z)=(200)/(100sqrt2)=sqrt2A` `(v)"Maximum current"=I_("rms")sqrt2=2A` `(vi)"voltage across"R=V_(R,"rms")=I_("rms")R=sqrt2xx100"volt"` `(viii)"max voltage across R "=sqrt2 V_(R,"rms")X_(C)=sqrt2xx100"volt"` `(ix)"max voltage acorss C"=sqrt2V_(C,"rms")=200"volt"` `(x) lt P gt =V_("rms")I_("rms")cos phi=200xxsqrt2xx (1)/(sqrt2)=200"volt"` `("xi") lt P_(R)=I_("rms")cos phi=200W` `("xii") lt P_(C) =0`

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