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In Angle PQR , PQ = 8 cm and RT = 6 cm. Find the area of[ ¡] angle PQR [ ¡¡] the length of QS |
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Answer» Let the BASE of the TRIANGLE be PQ=4 cm, then the height is RT=6 cm.Hence AREA of triangle = 21 base×height= 21 (4)(6)=12 cm 2 Now A=12 cm 2 Hence,21 PR×QS=12⟹ 21 ×8×QS=12⟹QS=3 cm |
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