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In answering a question on a multiple choice test, a student either knows the answer or guesses. Let `3/4`be the probability that he knows the answer and `1/4`be the probability that he guesses. Assuming that a student who guesses at the answer with probability 1/4. what is the probability that the student knows the answer given that he answers correctly.?

Answer» Probablity student knows the answer, `P(A) = 3/4`
Probablity student knows the answer, `P(B) = 1/4`
Probablity of correct answer when student knows the answer,`P(C/A)= 1`
Probablity of correct answer when student guesses the answer,`P(C/B)= 1/4`
So, probablity student gives answer correctly, when he knows the answer,
`P(A/C) = (P(A)*P(C/A))/(P(A)*P(C/A))+(P(B)*P(C/B))`
`=(3/4*1)/((3/4)+(1/4)(1/4))=(3/4)/(13/16)=12/13`


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