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In any `AC` circuit the emf `(e)` and the current `(i)` at any instant are given respectively by `e= E_(0)sin omega t` `i=I_(0) sin (omegat-phi)` The average power in the circuit over one cycle of `AC` isA. `(E_(0)I_(0))/2`B. `(E_(0)I_(0))/2 sin phi`C. `(E_(0)I_(0))/2 cos phi`D. `E_(0)I_(0)` |
Answer» Correct Answer - C The power is defined as the rate at which work is being done in the circuit. Power =rate of work done in one complete cycle. or `P_(av)=W/T` or `P_(av)=((E_(0)I_(0)cos phi)T//2)/T` or `P_(av)=(E_(0)I_(0)cos phi)/2` where `cos phi` is called the power factor of an `AC` circuit. |
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