In any `AC` circuit the emf `(e)` and the current `(i)` at any instant are given respectively by `e= E_(0)sin omega t` `i=I_(0) sin (omegat-phi)` The average power in the circuit over one cycle of `AC` isA. `(E_(0)I_(0))/(2)cosphi`B. `E_(0)I_(0)`C. `(E_(0)I_(0))/(2)`D. `(E_(0)I_(0))/(2)sin phi`

In any `AC` circuit the emf `(e)` and the current `(i)` at any instant

1.	In any `AC` circuit the emf `(e)` and the current `(i)` at any instant are given respectively by `e= E_(0)sin omega t` `i=I_(0) sin (omegat-phi)` The average power in the circuit over one cycle of `AC` isA. `(E_(0)I_(0))/(2)cosphi`B. `E_(0)I_(0)`C. `(E_(0)I_(0))/(2)`D. `(E_(0)I_(0))/(2)sin phi`
Answer» Correct Answer - A `e=E_(0)sin omegat` `i=I_(0) sin (omegat-phi)` `P_(av.)=e_("rms").I_("rms").cos phi` `(E_(0))/(sqrt2).(I_(0))/(sqrt2). cosphi = E_(0)I_(0)cosphi`

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In any `AC` circuit the emf `(e)` and the current `(i)` at any instant are given respectively by `e= E_(0)sin omega t` `i=I_(0) sin (omegat-phi)` The average power in the circuit over one cycle of `AC` isA. `(E_(0)I_(0))/(2)cosphi`B. `E_(0)I_(0)`C. `(E_(0)I_(0))/(2)`D. `(E_(0)I_(0))/(2)sin phi`

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