1.

In any reaction rate of reactant is double when concentration of reactant is increase in 4 time.If concentration of reaction is increase in 9 times than calciulate rate of reactant.

Answer»

4.5 TIMES
3 times
9 times
81 times

Solution :Order of reaction =2 , So,`r_(1)=k[R]^(x)` and
CONCENTRATION 4 times =`2^(2)` ,the rate =`2^(1)`
Concentration 9 times =`3^(2)` ,then rate will BECOMES 3 times


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