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In any triangle `A B C ,sin^2A-sin^2B+sin^2C`is always equal to`2sinAsinBcosC`(b) `2sinAcosBsinC``2sinAcosBcosC`(d) `2sinAsinBsinC`A. `2sin A sin B cosC`B. `2 sin A cos B sinC`C. `2 sin A cos B cos C`D. `2 sin A sin B sinC` |
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Answer» Correct Answer - B `sin^(2)A-sin^(2)sin^(2)C` `=sin(A+B)sin(A-B)+sin^(2)C` `=sinC(sin(A-B)+sinC)` `=sinC(sin(A-B)+sin(A+B))` `=2sin A cos B sin C`. |
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