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In any triangle ABC, find the least value of `(r_(1) + r_(2) + r_(3))/(r)` |
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Answer» Correct Answer - 9 We have already proved that `(1)/(r_(1)) + (1)/(r_(2)) + (1)/(r_(3)) = (1)/(r)` Now using A.M. `ge` H.M. we get `(r_(1) + r_(2) + r_(3))/(3) ge (3)/((1)/(r_(1)) + (1)/(r_(2)) + (1)/(r_(3))) = 3r` `rArr (r_(1) + r_(2) + r_(3))/(r) ge 9` |
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