In areversible reaction, study of its mechanism says that both the forward and reverse reaction follows first-order kinetics. If the halflife of forward reaction `(t_(1//2))_(f)` is `400 s` and that of reverse reaction `(t_(1//2))_(b)` is `250 s`, the equilibrium of the reaction isA. `1.6`B. `0.433`C. `0.625`D. `1.109`

In areversible reaction, study of its mechanism says that both the for

1.	In areversible reaction, study of its mechanism says that both the forward and reverse reaction follows first-order kinetics. If the halflife of forward reaction `(t_(1//2))_(f)` is `400 s` and that of reverse reaction `(t_(1//2))_(b)` is `250 s`, the equilibrium of the reaction isA. `1.6`B. `0.433`C. `0.625`D. `1.109`
Answer» Correct Answer - C `t_(1//2)=0.693/K` (for first-order kinetics) `K_(f)=0.693/400 s^(-1), K_(b)=0.693/250 s^(-1)` `K=K_(f)/K_(b)=250/400=0.625`

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