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In Arrhenius equation for a a certain reaction , the values of A and E_a (activation energy ) are 4xx10^(13)"sec"^(-1) and 98.6"kJ mol"^(-1) respectively. If the reaction is of order , at what temperature will its half life period be 10 minutes ? |
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Answer» Solution :ACCORDING to the Arrhenius equation, `k=Ae^(-E_a/(RT))` or `log_ek=log_eA-(E_a)/(RT)` or `2.303log_(10)k=2.303log_(10)A -E_a/(RT)` `t_(1//2)=(0.693)/k(0.693)/600` `k=(0.693)/(600)sec^(-1)(t_(1//2)=10min=600sec)` `=1.1xx10^(-3)sec^(-1)` Hence , LOG `(1.1xx10^(-3)` `=log(4xx10^(13))-(98.6xx10^3)/(2.303xx8.314xxT)` `T=310.95K` |
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