1.

In atom of any element when electron make transition from orbit of higher energy (n_(f)) to orbit of lower energy (n_(i)) equation representing wave number is given by ....... where n_(i)=1,n_(f)=2,3,4,…….

Answer»

`(1)/(lamda)=R[(1)/(n_(i)^(2))-(1)/(n_(f)^(2))]`
`(1)/(lamda)=RZ[(1)/(n_(i)^(2))-(1)/(n_(f)^(2))]`
`(1)/(lamda)=R[(1)/(n_(f)^(2))-(1)/(n_(i)^(2))]`
`(1)/(lamda)=RZ[(1)/(n_(f)^(2))-(1)/(n_(i)^(2))]`

SOLUTION :`(1)/(lamda)=RZ[(1)/(n_(f)^(2))-(1)/(n_(i)^(2))]`


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