In bFig. AB = AC and AD is the bisector of ∠BAC.(i) State three pa

1.	In bFig. AB = AC and AD is the bisector of ∠BAC.(i) State three pairs of equal parts in triangles ADB and ADC.(ii) Is ΔADB ≅ ΔADC? Givereasons.(iii) Is ∠B = ∠C? Give reasons.
Answer» ong>Answer: i) ans-AD=AD (common side) angle ADB=angle ADC=90° (SINCE AD is perpendicular to BC) AB=BC (GIVEN) ii) ans-Yes (by right angle Hypotenuse side or RHS) iii) ans-yes (angles OPPOSITE to equal sides of a triangle are equal) hope it will HELP

In bFig. AB = AC and AD is the bisector of ∠BAC.(i) State three pairs of equal parts in triangles ADB and ADC.(ii) Is ΔADB ≅ ΔADC? Givereasons.(iii) Is ∠B = ∠C? Give reasons.

Answer»

ong>Answer:

ans-AD=AD

(common side)

angle ADB=angle ADC=90°

(SINCE AD is perpendicular to BC)

AB=BC

ii)

ans-Yes

(by right angle Hypotenuse side or RHS)

iii)

ans-yes

(angles OPPOSITE to equal sides of a triangle are equal)

hope it will HELP