1.

In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is: (at mass Ag=108 , Br =80)

Answer»

`24`
`36`
`48`
`60`

Solution :`% X = ("ATOMIC MASS of Br")/("Molecular mass of AGBR") xx ("Wt. of AgBr")/("Wt. of organic BROMIDE")`
Thus`% Br = (80)/(188) xx (141)/(250) xx 100 = 24`.


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