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In Carius method of estimation of halogens, 250mg of an organic compound gave 141mg of AgBr. The percentage of bromine in the compound is : (at mass Ag=108 , Br=80) |
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Answer» Solution :Percentge of `Br` `=(80)/(188)xx("MASS of" AgBr)/("Wt.of compound")XX100` `=(80)/(188)xx(141)/(250)xx100=24%` |
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