1.

In Carius method of estimation of halogens, 250mg of an organic compound gave 141mg of AgBr. The percentage of bromine in the compound is : (at mass Ag=108 , Br=80)

Answer»

`24`<BR>`36`
`48`
`60`

Solution :Percentge of `Br`
`=(80)/(188)xx("MASS of" AgBr)/("Wt.of compound")XX100`
`=(80)/(188)xx(141)/(250)xx100=24%`


Discussion

No Comment Found