1.

In case of first order reactions

Answer»

`t_(3//4)=2t_(1//2)`
`t_(7//8)=3t_(1//2)`
`t_(0.99)=10t_(1//2)`
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Solution :`1to1/2to1/4to1/u,((2.303xxlog2)/(t_(1/2)))xxt_(0.99)=2.303log(100/0.01)`
`log2xx(t_(0.99))/(t_(2)^(1))=LOG10^(4),t_(0.99)=(4xxt_(1/2))/0.3010=13.289xxt_(1/2)=13.3xxt_(1/2)`


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