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In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to `22.3J` is done on the system. If the gas is taken from State A to B via a process in which the net heat absorbed by the system is `9.35 cal`., How much is the net work done by the system in the later case? (Take `1 cal.= 4.9J`) |
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Answer» Here, when the change is adiabatic, `DeltaQ= 0, DeltaW= -22.3J` If `DeltaU` is change in internal energy of the system, then as `DeltaQ= DeltaU+DeltaW` `0= DeltaU-22.3 or DeltaU= 22.3J` In the second case, `DeltaQ= 9.35 cal.= 9.35xx4.2J= 39.3J , DeltaW= ?` As `DeltaU+DeltaW=DeltaQ` `:. DeltaW= DeltaQ-DeltaU= 39.3-22.3= 17.0J` |
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