1.

In chemical equilibrium, the value of Delta n (number of molecules), is negative, then the relationship between K_(p) "and" K_(c) will be

Answer»

`K_(P)-K_(c) = 0`
`K_(c) = K_(P) XX (RT)^(+DELTAN)`
`K_(P) = K_(c) xx (RT)^(-Deltan)`
`K_(c) = 1/K_(p)`

SOLUTION :`Kp = Kc(RT)^(Deltang)`
Since, `Delta(NG)` is -ve
`Kc = Kp(RT)^(+Deltang)`


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