In chemical equilibrium, the vlue of `Deltan` (number of molecules of products-number of molecules of reactants) is negative, then the relationship between `K_(p)and K_(c)` will beA. `K_(p)-K_(c)=0`B. `K_(p)=K_(c)(RT)^(+Deltan)`C. `K_(p)=K_(c)(RT)^(-Deltan)`D. `K_(p)=(1)/(K_(c))`

In chemical equilibrium, the vlue of `Deltan` (number of molecules of

1.	In chemical equilibrium, the vlue of `Deltan` (number of molecules of products-number of molecules of reactants) is negative, then the relationship between `K_(p)and K_(c)` will beA. `K_(p)-K_(c)=0`B. `K_(p)=K_(c)(RT)^(+Deltan)`C. `K_(p)=K_(c)(RT)^(-Deltan)`D. `K_(p)=(1)/(K_(c))`
Answer» Correct Answer - B

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In chemical equilibrium, the vlue of `Deltan` (number of molecules of products-number of molecules of reactants) is negative, then the relationship between `K_(p)and K_(c)` will beA. `K_(p)-K_(c)=0`B. `K_(p)=K_(c)(RT)^(+Deltan)`C. `K_(p)=K_(c)(RT)^(-Deltan)`D. `K_(p)=(1)/(K_(c))`

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