1.

In chromium chloride(CrCl_(3),Cl^(-)ions have cubic close packed arragement andCr^(3+)ions are present in the octahedral holes. The fraction of the total number of holes occupied is

Answer»

`1//3`
`1//6`
`1//9`
`1//12`

Solution :In`CrCl _(3)`, for every, 3 `Cl^(-)`ions there is one`CR^(3+)`ions. THUS , if there are `3 Cl^(-)`ions in the packing, octahedral voids = 3, TETRAHEDRAL voids = 6. Total voids = 3 + 6 = 9 . As 1 `Cl^(3+)` ion is present in the void, therfore fractionof HOLES occupied`= 1//9`


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