Saved Bookmarks
| 1. |
In circuit shown in figure, terminal X is brought from point A to B. Then reading of ammeter . |
|
Answer» increases Raeading of ammeter `I_(0) = epsilon/R` `R = x+y` or `I_(0 )= epsilon/(x+y)`  ,  When sliding key is at any other position `I_(1) = epsilon/((R_0x)/(R_0+x) +y)` `Reading of ammeter `I = I_(1) (R_0)/(R_0+x)` `= (epsilon(R_0+x))/([R_0x+(R_0+y)] (R_0+x))` `= (epsilonR_0)/(R_0(x+y)+xy) = (epsilon)/((x+y)+(xy)/(R_0))` ,BRGT Hence `I' ltI_0` Hence the reading of ammeter first decreases then increases. |
|