1.

In circular coil, when number of turns is doubled and resistance becomes 1/4th of initial value, the inductance becomes

Answer»

8 times
2 times
4 times
No change

Solution :For a coil, `L=(mu_(0)pi N^(2)R)/(2)`, r = radius of coil.
`rArr (L)/(L.)=((N)/(N.))^(2)=((N)/(2N))^(2)=(1)/(4)rArr L.=4L`.
So, INDUCTANCE BECOMES 4 times of its initial.


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