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In compound microscope the magnification is 95, and the distance of object from objective lens 1/3.8 cm and focal length of objective is ¼ cm. What is the magnification of eye pieces when final image is formed at least distance of distinct vision :A. 5B. 10C. 100D. None |
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Answer» Correct Answer - A Compound microscope `M = m_0xxm_e` `M=(F_0)/(u+F_0)xxm_e` `implies95=(1//4)/(-1//3.8+1//4)m_e` `implies 95=19m_e " "impliesm_e=95/19=5` |
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