1.

In conditions of the previous problem find the frequency and the period of the variation of kinetic energy.

Answer»


Solution :The EXPRESSION for the kinetic energy is TRANSFORMED as follows:
`K=2.50cos^(2)(20pit+(3pi)/(4))=1.25[1+cos(40pit+(3pi)/(2))]=1.25(1+sin40pit)`
The FREQUENCY of energy oscillations is `v_(K)=40pi//(2PI)=20Hz`, the period is `T_(K)=0.05` s.


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