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In conventional television, signals are broadcast from towers to home receivers. Even when a receiver is not in direct view of a tower because of a hill or building, it can still intercept a signal if the signal diffracts enough around the obstacle, into the obstacle's "shadow region." Previously, television signals had a wavelength of about 50 cm, but digital television signals that are transmitted from towers have a wavelength of about 10 mm. (a) Did this change in wavelength increase or decrease the diffraction of the signals into the shadow regions of obstacles? Assume that a signal passes through an opening of 6.0 m width between two adjacent buildings. What is the angular spread of the central diffraction maximum out to the first minima) for wavelengths of (b) 50 cm and (c) 10 mm?

Answer»

Solution :(a) DIFFRACTION EFFECTS in GENERAL WOULD decrease, (b) 9.6, (c) 0.010 m.


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