1.

In corundum, oxide ions are arranged in hcp arrangement and the aluminium ions occupy two-third of the octahedral holes. Its formula is :

Answer»

`Al_(2)O_(4)`
`Al_(2)O_(3)`
`Al_(3)O_(4)`
`AlO_(2)`

Solution :In a close packed arrangement, there is one octahedral site corresponding to each atom constituting the lattice.
No. of oxide ions per UNIT CELL in hcp = 6.
No. of octahedral holes `= 6 xx1 = 6`
Formula of compound `=Al_(4) O_(6) ` or `Al_(2) O_(3)`


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