in ΔABC is a right angled triangle,right angled at B,AD is the median from A on side BC,CD=DB, prove that AC^2=AD^2+3DB^2

in ΔABC is a right angled triangle,right angled at B,AD is the median

1.	in ΔABC is a right angled triangle,right angled at B,AD is the median from A on side BC,CD=DB, prove that AC^2=AD^2+3DB^2
Answer» <html><body><p><strong>Answer:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/hey-479830" style="font-weight:bold;" target="_blank" title="Click to know more about HEY">HEY</a> here is your proof in above pics </p><p>pls <a href="https://interviewquestions.tuteehub.com/tag/mark-555248" style="font-weight:bold;" target="_blank" title="Click to know more about MARK">MARK</a> it as brainliest </p><p><strong>Step-by-step explanation:</strong></p><p>here I have solved this proof by 3 possible methods </p><p></p><p>so you can choose any of it with which you feel comfortable </p><p>any doubt in geometry or statistics ask <a href="https://interviewquestions.tuteehub.com/tag/soham-647182" style="font-weight:bold;" target="_blank" title="Click to know more about SOHAM">SOHAM</a> bhaiiya </p><p>they are my <a href="https://interviewquestions.tuteehub.com/tag/life-541672" style="font-weight:bold;" target="_blank" title="Click to know more about LIFE">LIFE</a> I just can't <a href="https://interviewquestions.tuteehub.com/tag/live-543270" style="font-weight:bold;" target="_blank" title="Click to know more about LIVE">LIVE</a> without these two </p></body></html>