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In damped oscillations damping froce is directly proportional to speed of ocillatior .If amplitude becomes half to its maximum value is 1 s, then after 2 s amplitude will be (`A_(0)`- initial amplitude)A. `(1)/(4)A_(0)`B. `(1)/(2)A_(0)`C. `A_(0)`D. `(sqrt(3)A_(0))/(2)` |
Answer» Correct Answer - A (a) Amplitude of damped oscillation is `A=A_(0)e^(-gammat)` `A=(A_(0))/(2)` where t=1s So, `(A_(0))/(2)=A_(0)e^(-gamma1)` or `e^(gamma)=2` After 2 s, `A=A_(0)e^(-gamma^(3))implies A=(A_(0))/(4)` |
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