1.

In davision -Germer experiment electron emitted from filament is accelerated by V volt.Its de-Broglie wavelength will be……..

Answer»

<P>`(sqrt(H))/(2Vem)`
`(h)/(sqrt(2Vem))`
`(sqrt(2Vem))/(h)`
`(2Vem)/(sqrt(h))`

SOLUTION :`ve=(1)/(2)mv^(2)`
`2Vem=m^(2)v^(2)`
2Vem=`p^(2) [because mv=p]`
`therefore =sqrt(2Vem)`
Now de-Broglie WAVELENGTH `lambda=(h)/(p)`
`therefore lambda=(h)/(sqrt(2Vem))`


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