In Davisson-Germer experiment, an electron beam of energy 60 eV is incident normally on a crystal surface. The maximum intensity is obtained at an angle of 60^(@) from the direction of incident beam, then the inter atomic distance in the crystal lattice will be :

In Davisson-Germer experiment, an electron beam of energy 60 eV is inc

1.	In Davisson-Germer experiment, an electron beam of energy 60 eV is incident normally on a crystal surface. The maximum intensity is obtained at an angle of 60^(@) from the direction of incident beam, then the inter atomic distance in the crystal lattice will be :
Answer» `1.83Å` `3.6 Å` `18Å` `0.18Å` SOLUTION :`LAMBDA= d sin phi=(1227)/(sqrt(V))` `d=(1227xx2)/(sqrt(3xx60))=1*83Å`

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In Davisson-Germer experiment, an electron beam of energy 60 eV is incident normally on a crystal surface. The maximum intensity is obtained at an angle of 60^(@) from the direction of incident beam, then the inter atomic distance in the crystal lattice will be :

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