1.

In Delhi on a polluted day, concentration of SO_(2) in air is 40ppm. Assuming density of air is 2gm/litre. How many gram of SO_(2) is present in 100 litre of air?

Answer»

4mg
4gm
`8xx10^(-3)kg`
8mg

Solution :`40ppm=("Mass of" SO_(2))/("Mass of AIR")xx10^(6)RARR"Mass of" SO_(2)=(40xx"Mass of air")/(10^(6))`
`d_("air")=("Mass of air")/(V_("air")(lit.))=(2GM)/(lit.)rArr"Mass of air"=2xx100=200gm`
Mass of `SO_(2)=(400xx200)/(10^(6))=8xx10^(-3)gmrArr 8mg`


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