InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
In `Delta ABC, "cot"(A)/(2) + "cot" (B)/(2) + "cot" (C)/(2)` is equal toA. `(Delta)/(r^(2))`B. `((a + b + c)^(2))/(abc) 2R`C. `(Delta )/(r)`D. `(Delta)/(Rr)` |
|
Answer» Correct Answer - A `cot.(A)/(2) + cot.(B)/(2) + cot.(C)/(2)` `= (s(s-a))/(Delta) + (s(s-b))/(Delta) + (s-(s -c))/(Delta)` `= (s)/(Delta) [3s - (a + b + c)] = (s^(2))/(Delta) = ((Delta//r)^(2))/(Delta) = (Delta)/(r^(2))` |
|