In `Delta ABC`, prove that: `(a+b+c)/(a-b+c)=cotA/2cotC/2`

1.	In `Delta ABC`, prove that: `(a+b+c)/(a-b+c)=cotA/2cotC/2`
Answer» RHS= `cotA/2.cotC/2` `=sqrt(s(s-a))/(s-b)(s-c).sqrt((s(s-c))/(s-a)(s-b)` `=sqrt(s^(2))/((s-b)^(2))=s/(s-b)=(2s)/(2s-2b)` `=(a+b+c)/(a+b+c-2b)=(a+b+c)/(a-b+c)`= LHS Hence Proved.

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