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In `DeltaABC`, a=16, b=12 and `angleB=30^(@)`, find sinA. |
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Answer» From sine rule `a/(sinA)=b/(sinB)` `rArr sinA=(asinB)/(b) = (16 sin30^(@))/(12)` `=(16 xx 1)/(12 xx 2)=2/3`. Ans. |
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