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In `DeltaABC, AP _|_BC, BQ_|_AC. B-P-C,A-Q-C,` then prove that `DeltaCPA~DeltaCQB`. If `AP=7, BQ=8, BC=12` then find AC. |
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Answer» In `DeltaCPA` and `DeltaCQB`, `/_CPA~=/_CQB` …..(Each of measure `90^(@)`) `/_ACP~=/_BCQ`……..(Common angle) `:.DeltaCPA~DeltaCQB` …….. ("AA" test of similarity) `:.(AP)/(BQ)=(AC)/(BC)` ……..(Corresponding sides of similar triangles are proportional) `:.(7)/(8)=(AC)/(12)`.........(Substituting the given values) `:.ACxx8=7xx12` `:.AC=10.5` |
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