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In `DeltaABC, " if " b^(2) + c^(2) = 2a^(2)`, then value of `(cotA)/(cot B + cot C)` isA. `(1)/(2)`B. `(3)/(2)`C. `(5)/(2)`D. `(5)/(3)` |
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Answer» Correct Answer - A `(cotA)/(cotB cotC) = ((R(b^(2) + c^(2) -a^(2)))/(abc))/((R(a^(2) + c^(2) -b^(2)))/(abc) + (R(a^(2) + b^(2) -c^(2)))/(abc))` `= (b^(2) + c^(2) -a^(2))/(2a^(2))` `= (2a^(2) -a^(2))/(2a^(2))` `= (1)/(2)` |
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