In `DeltaABC`, prove that: `a(cos^(2)C/3-cos^(2)B/2)=(b-c).cos^(2)A/2`

1.	In `DeltaABC`, prove that: `a(cos^(2)C/3-cos^(2)B/2)=(b-c).cos^(2)A/2`
Answer» LHS= `a(cos^(2)C/2-cos^(2)B/2)` `=a[(s(s-c))/(ab)-(s(s-b))/(ac)]` `=a.s/a[(s-c)/(b)-(s-b)/( C)]` `

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