In `DeltaABC`, prove that: `(c-bcosA)/(b-ccosA)=(cosB)/(cosC)`

1.	In `DeltaABC`, prove that: `(c-bcosA)/(b-ccosA)=(cosB)/(cosC)`
Answer» LHS `=(c-bcosA)/(b-ccosA)` `=((acosB+bcosA)-bcosA)/((acosC+ccosA)-ccosA)` (From projection formula) `=(acosB)/(acosC)=(cosB)/(cosC)= RHS` Hence Proved.

Discussion