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In deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of nlambda//a. Justify this by suitably dividing the slit to bring out the cancellation. |
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Answer» Solution :When a slit of width d is DIVIDED into n no. of smaller identical slits then width of each smaller slit will be, `d.=(d)/(n)""....(1)` Now, angle of diffraction for FIRST order MINIMUM is, `theta=(lamda)/(d.)` `=(lamda)/(d//n)` [From equation (1)] `:.theta=(nlamda)/(d)` At above angle of diffraction, we get zero intensity due to each smaller slit and so due to ENTIRE single big slit also we get zero intensity. |
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