1.

In differation angle of first minima of Fraunhoffer diffraction is (pi)/(6) width of slit d =......

Answer»

`lambda`
`2lambda`
`(lambda)/(2)`
`(lambda)/(6)`

SOLUTION :In `d sin THETA= N lambda, n=1, theta=(pi)/(6)`
`:. D=((1) lambda)/("sin" (pi)/(6))=( lambda)/((1)/(2))"" :. d=2lambda`


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