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In double-slit Experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distance screen is 0.1^(@). What is the spacing between the two slits? |
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Answer» Solution :Here wavelength of light `l=600nm=6XX10^(-7)m` and ANGULAR width of fringe a`=0.1^(@)` As angular width `ALPHA=(lamda)/(d)`, hence spacing between the two slits `d=(lamda)/(alpha)` `therefore d=(6xx10^(-7)m)/((0.1xx(pi)/(180))rad)=3.43xx10^(-4)mcong3.4xx10^(-4)m`. |
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