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In double slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distance screen is 0.1^(@). What is the spacing between the two slits? |
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Answer» Solution :` d sin THETA = n lamda` `d =(n lamda)/( sin theta)=( 1xx600xx10^(-9))/(sin(0.1)^(@))=(6XX10^(-7))/0.0017=3.5xx10^(-4)m` |
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