In double slit pattern (lambda = 6000 Å), the zero order and tenth order maxima fall at 12.34 mm and 14.73 mm from a particular reference point. If lambda is changed to 5000 Å, find the position of zero order and tenth order fringes, other set up being same :

In double slit pattern (lambda = 6000 Å), the zero order and tenth or

1.	In double slit pattern (lambda = 6000 Å), the zero order and tenth order maxima fall at 12.34 mm and 14.73 mm from a particular reference point. If lambda is changed to 5000 Å, find the position of zero order and tenth order fringes, other set up being same :
Answer» `6.2 mm` `14.53 mm` `7.2 mm` 94 mm Solution :`beta = (14.73 - 12.34)/(10) = 0.239 mm, beta = (lambdaD)/(d)` `THEREFORE 0.239 xx 10^(-3) = (6000 xx 10^(-10)D)/(d)` or `(D)/(d) = 398.3` When `lambda. = 5000 Å` `beta. = (lambda.D)/(d) = 0.219 mm`. The zero ORDER fringe will OCCUR at same position, at 12.34 mm. The 10th order at `12.34 + 10 xx 0.219= 14.53 mm`.

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In double slit pattern (lambda = 6000 Å), the zero order and tenth order maxima fall at 12.34 mm and 14.73 mm from a particular reference point. If lambda is changed to 5000 Å, find the position of zero order and tenth order fringes, other set up being same :

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