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| 1. |
In ΔPQR, PD⊥QR such that D lies on QR, if PQ = a, PR = b, QD = c and DR = d, then prove that (a+b) (a-b) = (c+d) (c-d). |
| Answer» In ΔPQR, PD⊥QR such that D lies on QR, if PQ = a, PR = b, QD = c and DR = d, then prove that (a+b) (a-b) = (c+d) (c-d). | |