1.

In dry cell the reaction which takes place at the zinc anode is

Answer»

`Zn^(2+)+2e^(-)toZn_((s))`
`Zn_((s))TOZN^(2+)+2e^(-)`
` MN^(2+)+2e^(0)toMn_((s))`
`Mn_((s))toMn^(+)+E^(+)+1.5V`

SOLUTION :At anode: `Zn_((s))toZn^(2+)+2e^(-)`.


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