1.

In Duma'smethod for estimation of nitrogen 0.25 g of anorganic compound gave 40 mL of nitrogencollected at 300 K temeprature and 725 nn pressure. If the aqueous tension at 300 K is 25 mm. the percentage of nitrogen in the compound is

Answer»

<P>`18.20`
`16.76`
`15.76`
`17.36`

SOLUTION :Mass of organic comp. `= 0.25 g`
`V_(1) = 40 ml`
`T_(1) = 300 K`
`P_(1) = 725 - 25 = 700 nm` of `Hg`
`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))`
`V_(2) = (700xx 40 xx 273)/(300 xx 760) = 323.52ml`
`%` of `N = (28 xx V xx 100)/(22400 xx " mass of org.com")`
`= (28 xx 33.52 xx 100)/(22400 xx 0.25) = 16.76`


Discussion

No Comment Found

Related InterviewSolutions